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Wild Mass Guessing:
Dividing by Zero
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Dividing by Zero:

 1 Professor Metallica, Mon, 22nd Nov '10 9:50:56 AM from The nth dimension! Relationship Status: Married to my murderer
I design worlds. Or, I hope to.
Okay, so everybody knows that anything multiplied by zero is zero. 6x0=0. what if you reverse that? 0/0=6. of course, all numbers do this. 3x0=0. so, 0/0=3. therefore, if zero divided by zero is every number, then should 0/0= {R} (all real numbers) or infinity?
Don't fear the Reaper. Make him fear you.
 2 BlackWolfe, Mon, 22nd Nov '10 1:59:09 PM from Lost in Austin
0/0 should equal a set of all numbers, real or imaginary. Since that's meaningless and since that only works for dividing zero by zero, we just say it can't be done.
But soft! What rock through yonder window breaks? It is a brick! And Juliet is out cold.
 3 Ponicalica, Mon, 22nd Nov '10 3:36:28 PM from facing Buttercup
The division operator is defined on R (R\{0}). Division by zero is undefined.
It's a straight vertical line so of course the range will be all reals. This isn't really new.
 
insane genius
Dividing anything by zero should equal infinity, but it doesn't, (partly) because you can't apply math to infinity.
 6 Tzetze, Fri, 26th Nov '10 9:59:57 AM from a converted church in Venice, Italy
DUMB
No, not really. The limit of 1/0 is ∞ while the limit of -1/0 is -∞, and such. And you can too apply mathematics to infinity, it's just different.
insane genius
Maybe I should rephrase that, you can apply math to infinity, you're just not going to get any meaningful results. Also, -∞ = ∞, because infinity is both positive and negative. ( So I'm still right. And how do you get the ∞ to come out? )

edited 27th Nov '10 5:04:41 AM by satannstuff

 8 BlackWolfe, Sat, 27th Nov '10 5:03:46 AM from Lost in Austin
Like this: ∞

Also:

∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
Check it out, it's a knotwork border for my post!
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞

Edit: Dammit.

edited 27th Nov '10 5:04:36 AM by BlackWolfe

But soft! What rock through yonder window breaks? It is a brick! And Juliet is out cold.
insane genius
That's not very helpful, I just copied it from tzetze's post.
 10 BlackWolfe, Sat, 27th Nov '10 5:10:34 AM from Lost in Austin
That's what I'd done, but putting it in a pothole converts it over. Which is why the "dammit" edit.

∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
becomes
∞ over and over

edited 27th Nov '10 5:10:55 AM by BlackWolfe

But soft! What rock through yonder window breaks? It is a brick! And Juliet is out cold.
 11 Tzetze, Sat, 27th Nov '10 10:13:49 AM from a converted church in Venice, Italy
DUMB
Maybe I should rephrase that, you can apply math to infinity, you're just not going to get any meaningful results.

Oh sure you can. 20 = ℵ1, for example.

edited 27th Nov '10 10:14:01 AM by Tzetze

insane genius
You really want to go there?

ℵ0 = ∞

ℵ1 = ∞

ℵ0 = ℵ1 = ∞

The whole idea that you can define sets of infinity is just plain wrong. Both sets of numbers are infinite, if ℵ0 is infinite, and ℵ1 is infinite, both must be the same size. Just because the numbers in ℵ1 occur more frequently than those in ℵ0 doesn't mean there are more of them. You can't even describe infinity in terms of size or numbers because it is all sizes and numbers at once.

( Nothing personal, by the way, it's just that this transfinite stuff really bugs me. )

edited 28th Nov '10 4:18:42 AM by satannstuff

 13 Major Tom, Sun, 28th Nov '10 6:51:23 AM Relationship Status: Barbecuing
Eye'm the cutest!
Anything divided by zero is inherently a hyperbolic equation and thus not a mathematical function at the asymptote.

However the asymptote of such equations has real solutions even when divided by zero. Simply put, you have three solutions: ∞, -∞, and 0. All at the same time. Which is why things puke up an error on calculators and computers and teachers tell you don't bother calculating. It's the same answers no matter how the equation is designed.
Endless Conflict: Every war ends in time, even supposedly this one.
 14 Ponicalica, Sun, 28th Nov '10 7:18:23 AM from facing Buttercup
You are wrong. There is no bijection between the set Z and the set 2Z, therefore they have different cardinality.
insane genius
∞ = ∞

No matter how you try to divide it up, it's still infinite, size doesn't apply to infinity, to think that it does is just naive.
 16 Professor Metallica, Mon, 29th Nov '10 9:53:21 AM from The nth dimension! Relationship Status: Married to my murderer
I design worlds. Or, I hope to.
Seriously, guys... I'm only taking algebra 1. I'm a freshman in high school. sad
Don't fear the Reaper. Make him fear you.
insane genius
Don't worry, you're not going to have to learn this in high school. smile
 18 Tzetze, Tue, 30th Nov '10 9:47:25 AM from a converted church in Venice, Italy
DUMB
No matter how you try to divide it up, it's still infinite, size doesn't apply to infinity, to think that it does is just naive.

To think that it doesn't is denying about a century's worth of math. We can get useful results by recognizing different infinities.
insane genius
A century's worth of math has failed to prove CH, if you want to try go right ahead, I'm not going anywhere.
 20 Tzetze, Wed, 1st Dec '10 8:10:07 AM from a converted church in Venice, Italy
DUMB
The continuum hypothesis? If all infinities are equal as you insist, CH isn't even possible to formulate.
insane genius
That's my point. ( Nice avatar by the way, that's like your third, this week? tongue )

edited 2nd Dec '10 1:20:16 AM by satannstuff

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Total posts: 21
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